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Simplify a bit

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The expression can't be negative. It's a Pythagorean sum.

Change-Id: Ic07783c5291da71de6701a139227def2f1c4f77b
Reviewed-on: https://gerrit.libreoffice.org/c/core/+/175989
Tested-by: Jenkins
Reviewed-by: Mike Kaganski <mike.kaganski@collabora.com>
This commit is contained in:
Mike Kaganski 2024-11-04 21:06:15 +02:00
parent 9e3803ae43
commit 35b3abf583
1 changed files with 1 additions and 14 deletions
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15
basegfx/source/polygon/b2dsvgpolypolygon.cxx
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@ -543,20 +543,7 @@ namespace basegfx::utils
// of radicant solved for fRY,
// with s=fRX/fRY)
const double fRatio(fRX/fRY);
const double fRadicant2(
p1_prime.getY()*p1_prime.getY() +
p1_prime.getX()*p1_prime.getX()/(fRatio*fRatio));
if( fRadicant2 < 0.0 )
{
// only trivial solution, one
// of the axes 0 -> straight
// line segment according to
// SVG spec
aCurrPoly.append(B2DPoint(nX, nY));
continue;
}
fRY=sqrt(fRadicant2);
fRY=std::hypot(p1_prime.getY(), p1_prime.getX()/fRatio);
fRX=fRatio*fRY;
// keep center_prime forced to (0,0)