Fix dictionnary -> dictionary

It passed "make check" on Linux.

Change-Id: I893b7873f3a7d3f43bf742f2ee126524310dfafb
Reviewed-on: https://gerrit.libreoffice.org/61029
Reviewed-by: Julien Nabet <serval2412@yahoo.fr>
Tested-by: Julien Nabet <serval2412@yahoo.fr>
This commit is contained in:
Andrea Gelmini 2018-09-26 18:04:06 +02:00 committed by Julien Nabet
parent 81cf79d1af
commit 598f2ee618

View file

@ -66,31 +66,31 @@
</xs:restriction>
</xs:simpleType>
</xs:attribute>
<!-- set by dictionnary, else it is "thickmathspace" -->
<!-- set by dictionary, else it is "thickmathspace" -->
<xs:attribute name="lspace">
<xs:simpleType>
<xs:union memberTypes="length-with-unit named-space"/>
</xs:simpleType>
</xs:attribute>
<!-- set by dictionnary, else it is "thickmathspace" -->
</xs:attribute>
<!-- set by dictionary, else it is "thickmathspace" -->
<xs:attribute name="rspace">
<xs:simpleType>
<xs:union memberTypes="length-with-unit named-space"/>
</xs:simpleType>
</xs:attribute>
<!-- set by dictionnary, else it is "false" -->
<!-- set by dictionary, else it is "false" -->
<xs:attribute name="fence" type="xs:boolean"/>
<!-- set by dictionnary, else it is "false" -->
<!-- set by dictionary, else it is "false" -->
<xs:attribute name="separator" type="xs:boolean"/>
<!-- set by dictionnary, else it is "false" -->
<!-- set by dictionary, else it is "false" -->
<xs:attribute name="stretchy" type="xs:boolean"/>
<!-- set by dictionnary, else it is "true" -->
<!-- set by dictionary, else it is "true" -->
<xs:attribute name="symmetric" type="xs:boolean"/>
<!-- set by dictionnary, else it is "false" -->
<!-- set by dictionary, else it is "false" -->
<xs:attribute name="movablelimits" type="xs:boolean"/>
<!-- set by dictionnary, else it is "false" -->
<!-- set by dictionary, else it is "false" -->
<xs:attribute name="accent" type="xs:boolean"/>
<!-- set by dictionnary, else it is "false" -->
<!-- set by dictionary, else it is "false" -->
<xs:attribute name="largeop" type="xs:boolean"/>
<xs:attribute name="minsize">
<xs:simpleType>