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xmloff : no need to use OUString literal for comparison

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Change-Id: I2b8f75ec56d93003d8c9c14b3cad1e3978cc6a39
Reviewed-on: https://gerrit.libreoffice.org/c/core/+/165227
Tested-by: Jenkins
Reviewed-by: Arnaud Versini <arnaud.versini@pm.me>
This commit is contained in:
Arnaud VERSINI 2024-03-24 17:18:36 +01:00 committed by Arnaud Versini
parent 0d859cee05
commit f16d04c95f
3 changed files with 6 additions and 6 deletions
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2
xmloff/source/script/XMLEventExport.cxx
View file

@ -185,7 +185,7 @@ void XMLEventExport::ExportEvent(
{
// search for EventType value and then delegate to EventHandler
const PropertyValue* pValue = std::find_if(rEventValues.begin(), rEventValues.end(),
[](const PropertyValue& rValue) { return u"EventType"_ustr == rValue.Name; });
[](const PropertyValue& rValue) { return u"EventType" == rValue.Name; });
if (pValue == rEventValues.end())
return;

2
xmloff/source/script/XMLScriptExportHandler.cxx
View file

@ -53,7 +53,7 @@ void XMLScriptExportHandler::Export(
for(const auto& rValue : rValues)
{
if (u"Script"_ustr == rValue.Name)
if (u"Script" == rValue.Name)
{
OUString sTmp;
rValue.Value >>= sTmp;

8
xmloff/source/style/prstylei.cxx
View file

@ -627,16 +627,16 @@ void XMLPropStyleContext::translateNameBasedDrawingLayerFillStyleDefinitionsToSt
const OUString& rPropName = rMapper->GetEntryAPIName(a.mnIndex);
XmlStyleFamily aStyleFamily(XmlStyleFamily::DATA_STYLE);
if(rPropName == u"FillGradientName"_ustr
|| rPropName == u"FillTransparenceGradientName"_ustr)
if(rPropName == u"FillGradientName"
|| rPropName == u"FillTransparenceGradientName")
{
aStyleFamily = XmlStyleFamily::SD_GRADIENT_ID;
}
else if(rPropName == u"FillHatchName"_ustr)
else if(rPropName == u"FillHatchName")
{
aStyleFamily = XmlStyleFamily::SD_HATCH_ID;
}
else if(rPropName == u"FillBitmapName"_ustr)
else if(rPropName == u"FillBitmapName")
{
aStyleFamily = XmlStyleFamily::SD_FILL_IMAGE_ID;
}