office-gobmx/bin/find-most-common-warn-messages.py
Noel Grandin 1ac17afea6 only print the top 20 warnings
Change-Id: I85309b7d805e59da49adae74b7df21bd048deb03
2017-09-29 10:37:47 +02:00

39 lines
1.3 KiB
Python
Executable file

#!/usr/bin/python
# A script to search our test logs and sort the messages by how common they are so we can start to
# reduce the noise a little.
import sys
import re
import io
import subprocess
# find . -name '*.log' | xargs grep -h 'warn:' | sort | uniq -c | sort -n --field-separator=: --key=5,6
process = subprocess.Popen("find workdir -name '*.log' | xargs grep -h 'warn:' | sort",
shell=True, stdout=subprocess.PIPE, universal_newlines=True)
messages = dict() # dict of sourceAndLine->count
sampleOfMessage = dict() # dict of sourceAndLine->string
for line in process.stdout:
line = line.strip()
# a sample line is:
# warn:sw:18790:1:sw/source/core/doc/DocumentRedlineManager.cxx:98: redline table corrupted: overlapping redlines
tokens = line.split(":")
sourceAndLine = tokens[4] + ":" + tokens[5]
if (sourceAndLine in messages):
messages[sourceAndLine] = messages[sourceAndLine] + 1
else:
messages[sourceAndLine] = 1
sampleOfMessage[sourceAndLine] = line[line.find(tokens[6]):]
tmplist = list() # set of tuple (count, sourceAndLine)
for key, value in messages.iteritems():
tmplist.append([value,key])
print( "The top 20 warnings" )
print
for i in sorted(tmplist, key=lambda v: v[0])[-20:]:
print( "%6d %s %s" % (i[0], i[1], sampleOfMessage[i[1]]) )